Permutations (Without Repitition)
In the prior lesson, we stated that a permutation is an arrangement of items where the specific sequence is important. In these types of permutations, we assume no repetition. This means once an item is placed in a position, it cannot be selected again. The formula is:Where:
- P: Represents Permutations (the count of possible arrangements).
- n: The total number of distinct items available to choose from.
- r: The number of items being selected and arranged.
Note that P(n,r) is also often written as nPr
It is important to
I. Fundamental Counting Principle
The fundamental principle of counting (aka, Rule of Products) is a basic concept used to determine the total number of possible outcomes in a situation where there are multiple independent events. It allows us to count a large number of possibilities without needing to list each one individually.Example: The Ice Cream Shop
You can choose a cone: Waffle or Sugar (2 options).
You can choose a flavor: Vanilla, Chocolate, or Strawberry (3 options).
How many distinct ice cream cones can you make?
2 x 3 = 6 possibilities
II. From Counting to Factorials (n!)
Now let's apply that same counting principle to arranging objects.
Example: Arranging Books
Imagine you have 3 different books (A, B, and C) and you want to put them in order on a shelf. How many different ways can you arrange them?
Example: Arranging Books
Imagine you have 3 different books (A, B, and C) and you want to put them in order on a shelf. How many different ways can you arrange them?
- Slot 1: How many choices do you have for the first spot? 3 (A, B, or C).
- Slot 2: You put one book down. How many are left for the second spot? 2.
- Slot 3: You put the second book down. How many are left? 1.
3 x 2 x 1 = 6 arrangements
In mathematics, we arrange items so often that we created a shorthand symbol for "multiplying a number by every integer smaller than it down to 1." This is the Factorial (!).
5! = 5 x 4 x 3 x 2 x 1
3! = 3 x 2 x 1
1! = 1
Note the special case of the factorial of 0 = 1
0! = 1
n! = n x (n-1) x (n-2) x ... x 1
n! = n x (n-1) x (n-2) x ... x 1
Key Takeaway: Factorials (
This is where many students get lost. What if we don't want to arrange all the books? What if we have a big group, but we only want to arrange a few of them?
This is called a Permutation.
n = Total items available.r = Number of items we are actually choosing and arranging.
Let's use the Fundamental Counting Principle again.
Finding the Formula
How do we represent that "partial factorial" mathematically?
We calculated: 8 x 7 x 6.
We know that the full factorial is: 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
We want to mathematically "remove" the bold part we didn't use. In multiplication, we "remove" things by dividing.
The part we want to remove (5 x 4 x 3 x 2 x 1) is actually just 5!.
So, we can write our calculation as:
Where did the 5 come from? The5 is the number of people who lost (did not get a medal).
Scenario: Eight runners are in a race (
Gold Medal: Any of the
8 runners can win.Silver Medal: The winner can't win twice, so
7 runners are left.Bronze Medal: The top two are occupied, so
6 runners are left.
Using the Counting Principle:
8 x 7 x 6 - 366 waysFinding the Formula
How do we represent that "partial factorial" mathematically?
We calculated: 8 x 7 x 6.
We know that the full factorial is: 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
We want to mathematically "remove" the bold part we didn't use. In multiplication, we "remove" things by dividing.
The part we want to remove (5 x 4 x 3 x 2 x 1) is actually just 5!.
So, we can write our calculation as:
Where did the 5 come from? The
5 = 8 - 3
So the formula is actually
This leads us directly to the formula for permutations (nPr)
In practice, when solving these problems you will likely just use a shorthand method for what the formula formally represents. That is, you will:
1. Look at r to find how many numbers will be in your multiplication chain.
2. Then start with n as the first number in your chain.
3. Multiply by decreasing integers (n - 1, n - 2, etc)
4. Stop when you have reached r numbers.
V. Solving Permutations
I'll call this the countdown method
Example:
Solve for P(6, 3)
Step1: We look at r (which here is 3). This means you need to multiply 3 numbers.
Step 2: Start with n (for this problem is 6)
Step 3: Multiply downward until you have 3 numbers in your chain:
6 x 5 x 4 = 120
Now I'll solve using the formula:
P(6, 3) = 6 x 5 x 4 x 3 x 2 x 1/ 3 x 2 x 1
P(6, 3) = 720/6 = 120
Gemini AI
https://www.geeksforgeeks.org/maths/fundamental-principle-of-counting/
https://www.mathsisfun.com/data/basic-counting-principle.html
https://en.wikipedia.org/wiki/Rule_of_product




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